Integrand size = 24, antiderivative size = 116 \[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=\frac {21901 \sqrt {1-2 x} \sqrt {3+5 x}}{12800}-\frac {1991 (1-2 x)^{3/2} \sqrt {3+5 x}}{1280}-\frac {181}{480} (1-2 x)^{3/2} (3+5 x)^{3/2}-\frac {3}{40} (1-2 x)^{3/2} (3+5 x)^{5/2}+\frac {240911 \arcsin \left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{12800 \sqrt {10}} \]
-181/480*(1-2*x)^(3/2)*(3+5*x)^(3/2)-3/40*(1-2*x)^(3/2)*(3+5*x)^(5/2)+2409 11/128000*arcsin(1/11*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)-1991/1280*(1-2*x)^( 3/2)*(3+5*x)^(1/2)+21901/12800*(1-2*x)^(1/2)*(3+5*x)^(1/2)
Time = 0.15 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.67 \[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=\frac {10 \sqrt {1-2 x} \left (-190161-18795 x+1233700 x^2+1660000 x^3+720000 x^4\right )-722733 \sqrt {30+50 x} \arctan \left (\frac {\sqrt {\frac {5}{2}-5 x}}{\sqrt {3+5 x}}\right )}{384000 \sqrt {3+5 x}} \]
(10*Sqrt[1 - 2*x]*(-190161 - 18795*x + 1233700*x^2 + 1660000*x^3 + 720000* x^4) - 722733*Sqrt[30 + 50*x]*ArcTan[Sqrt[5/2 - 5*x]/Sqrt[3 + 5*x]])/(3840 00*Sqrt[3 + 5*x])
Time = 0.19 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.13, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {90, 60, 60, 60, 64, 223}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sqrt {1-2 x} (3 x+2) (5 x+3)^{3/2} \, dx\) |
\(\Big \downarrow \) 90 |
\(\displaystyle \frac {181}{80} \int \sqrt {1-2 x} (5 x+3)^{3/2}dx-\frac {3}{40} (1-2 x)^{3/2} (5 x+3)^{5/2}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {181}{80} \left (\frac {11}{4} \int \sqrt {1-2 x} \sqrt {5 x+3}dx-\frac {1}{6} (1-2 x)^{3/2} (5 x+3)^{3/2}\right )-\frac {3}{40} (1-2 x)^{3/2} (5 x+3)^{5/2}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {181}{80} \left (\frac {11}{4} \left (\frac {11}{8} \int \frac {\sqrt {1-2 x}}{\sqrt {5 x+3}}dx-\frac {1}{4} (1-2 x)^{3/2} \sqrt {5 x+3}\right )-\frac {1}{6} (1-2 x)^{3/2} (5 x+3)^{3/2}\right )-\frac {3}{40} (1-2 x)^{3/2} (5 x+3)^{5/2}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {181}{80} \left (\frac {11}{4} \left (\frac {11}{8} \left (\frac {11}{10} \int \frac {1}{\sqrt {1-2 x} \sqrt {5 x+3}}dx+\frac {1}{5} \sqrt {1-2 x} \sqrt {5 x+3}\right )-\frac {1}{4} (1-2 x)^{3/2} \sqrt {5 x+3}\right )-\frac {1}{6} (1-2 x)^{3/2} (5 x+3)^{3/2}\right )-\frac {3}{40} (1-2 x)^{3/2} (5 x+3)^{5/2}\) |
\(\Big \downarrow \) 64 |
\(\displaystyle \frac {181}{80} \left (\frac {11}{4} \left (\frac {11}{8} \left (\frac {11}{25} \int \frac {1}{\sqrt {\frac {11}{5}-\frac {2}{5} (5 x+3)}}d\sqrt {5 x+3}+\frac {1}{5} \sqrt {1-2 x} \sqrt {5 x+3}\right )-\frac {1}{4} (1-2 x)^{3/2} \sqrt {5 x+3}\right )-\frac {1}{6} (1-2 x)^{3/2} (5 x+3)^{3/2}\right )-\frac {3}{40} (1-2 x)^{3/2} (5 x+3)^{5/2}\) |
\(\Big \downarrow \) 223 |
\(\displaystyle \frac {181}{80} \left (\frac {11}{4} \left (\frac {11}{8} \left (\frac {11 \arcsin \left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{5 \sqrt {10}}+\frac {1}{5} \sqrt {1-2 x} \sqrt {5 x+3}\right )-\frac {1}{4} (1-2 x)^{3/2} \sqrt {5 x+3}\right )-\frac {1}{6} (1-2 x)^{3/2} (5 x+3)^{3/2}\right )-\frac {3}{40} (1-2 x)^{3/2} (5 x+3)^{5/2}\) |
(-3*(1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/40 + (181*(-1/6*((1 - 2*x)^(3/2)*(3 + 5*x)^(3/2)) + (11*(-1/4*((1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) + (11*((Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/5 + (11*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(5*Sqrt[10]) ))/8))/4))/80
3.23.77.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Simp [2/b Subst[Int[1/Sqrt[c - a*(d/b) + d*(x^2/b)], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[c - a*(d/b), 0] && ( !GtQ[a - c*(b/d), 0] || PosQ[b])
Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p _.), x_] :> Simp[b*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 2))), x] + Simp[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(d*f*(n + p + 2)) Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt [a])]/Rt[-b, 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && NegQ[b]
Time = 3.61 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.89
method | result | size |
risch | \(-\frac {\left (144000 x^{3}+245600 x^{2}+99380 x -63387\right ) \left (-1+2 x \right ) \sqrt {3+5 x}\, \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{38400 \sqrt {-\left (-1+2 x \right ) \left (3+5 x \right )}\, \sqrt {1-2 x}}+\frac {240911 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{256000 \sqrt {1-2 x}\, \sqrt {3+5 x}}\) | \(103\) |
default | \(\frac {\sqrt {3+5 x}\, \sqrt {1-2 x}\, \left (2880000 x^{3} \sqrt {-10 x^{2}-x +3}+4912000 x^{2} \sqrt {-10 x^{2}-x +3}+722733 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )+1987600 x \sqrt {-10 x^{2}-x +3}-1267740 \sqrt {-10 x^{2}-x +3}\right )}{768000 \sqrt {-10 x^{2}-x +3}}\) | \(104\) |
-1/38400*(144000*x^3+245600*x^2+99380*x-63387)*(-1+2*x)*(3+5*x)^(1/2)/(-(- 1+2*x)*(3+5*x))^(1/2)*((1-2*x)*(3+5*x))^(1/2)/(1-2*x)^(1/2)+240911/256000* 10^(1/2)*arcsin(20/11*x+1/11)*((1-2*x)*(3+5*x))^(1/2)/(1-2*x)^(1/2)/(3+5*x )^(1/2)
Time = 0.24 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.62 \[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=\frac {1}{38400} \, {\left (144000 \, x^{3} + 245600 \, x^{2} + 99380 \, x - 63387\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {240911}{256000} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \]
1/38400*(144000*x^3 + 245600*x^2 + 99380*x - 63387)*sqrt(5*x + 3)*sqrt(-2* x + 1) - 240911/256000*sqrt(10)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3))
\[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=\int \sqrt {1 - 2 x} \left (3 x + 2\right ) \left (5 x + 3\right )^{\frac {3}{2}}\, dx \]
Time = 0.31 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.60 \[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=-\frac {3}{8} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} x - \frac {289}{480} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} + \frac {1991}{640} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {240911}{256000} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) + \frac {1991}{12800} \, \sqrt {-10 \, x^{2} - x + 3} \]
-3/8*(-10*x^2 - x + 3)^(3/2)*x - 289/480*(-10*x^2 - x + 3)^(3/2) + 1991/64 0*sqrt(-10*x^2 - x + 3)*x - 240911/256000*sqrt(10)*arcsin(-20/11*x - 1/11) + 1991/12800*sqrt(-10*x^2 - x + 3)
Leaf count of result is larger than twice the leaf count of optimal. 203 vs. \(2 (83) = 166\).
Time = 0.31 (sec) , antiderivative size = 203, normalized size of antiderivative = 1.75 \[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=\frac {1}{128000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (8 \, {\left (60 \, x - 119\right )} {\left (5 \, x + 3\right )} + 6163\right )} {\left (5 \, x + 3\right )} - 66189\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 184305 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {7}{6000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (40 \, x - 59\right )} {\left (5 \, x + 3\right )} + 1293\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 4785 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {87}{2000} \, \sqrt {5} {\left (2 \, {\left (20 \, x - 23\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 143 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {9}{25} \, \sqrt {5} {\left (11 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + 2 \, \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}\right )} \]
1/128000*sqrt(5)*(2*(4*(8*(60*x - 119)*(5*x + 3) + 6163)*(5*x + 3) - 66189 )*sqrt(5*x + 3)*sqrt(-10*x + 5) - 184305*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt (5*x + 3))) + 7/6000*sqrt(5)*(2*(4*(40*x - 59)*(5*x + 3) + 1293)*sqrt(5*x + 3)*sqrt(-10*x + 5) + 4785*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) + 87/2000*sqrt(5)*(2*(20*x - 23)*sqrt(5*x + 3)*sqrt(-10*x + 5) - 143*sqrt(2 )*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) + 9/25*sqrt(5)*(11*sqrt(2)*arcsin(1 /11*sqrt(22)*sqrt(5*x + 3)) + 2*sqrt(5*x + 3)*sqrt(-10*x + 5))
Timed out. \[ \int \sqrt {1-2 x} (2+3 x) (3+5 x)^{3/2} \, dx=\int \sqrt {1-2\,x}\,\left (3\,x+2\right )\,{\left (5\,x+3\right )}^{3/2} \,d x \]